How many ne atoms are contained in 32.0 g of the element?

Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms20.18 g
x32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

9.55*10²³ Ne atoms are contained in 32 g of the element.

Ithink is a because if say increased in electronegativity