Using the balanced equation given below, calculate the number of moles of CaBr2 produced in the reaction of 5.0 moles of AlBr3. moles CaBr2 *your answer should be written as X. X

2AlBr3 + 3CaO —> Al2O3 + 3CaBr2

7.5 moles of CaBr2 are produced

Explanation:

Based on the equation:

2AlBr3 + 3CaO → Al2O3 + 3CaBr2

2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.

Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:

5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =