How many quantum numbers are same for 11th and 12th electrons of Magnesium?

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Explanation:

The four quantum numbers determine the state of the electron, and are

n

is the distance of the orbital from the nucleus (

1

,

2

,

3

,

4

etc),

l

is the shape of the orbital (

0

→

n

−

1

)

m

l

is the orientation of the orbital in space (

−

l

→

+

l

), and

m

s

is the spin of the electrons inside the orbital (

−

1

2

or

+

1

2

).

The electronic configuration for magnesium is

1

s

2

2

s

2

2

p

6

3

s

2

. The outermost electron is one in the

3

s

orbital, which means that

n

=

3

.

It also means that

l

=

0

, since

s

is basically shorthand for the orbital shape of

l

=

0

.

m

l

can range from

−

l

to

+

l

, but since

l

=

0

, then

m

l

must also be

0

.

Finally,

m

s

can be either one since there are two electrons in the

3

s

orbital and it doesn't really matter which spin you choose.

Putting all of these together, the final quantum numbers of a magnesium atom are

3

,

0

,

0

,

±

1

2