What volume is occupied by5.3 mol of c02 at 28c and a pressure of .998 atm

V  = 131.23 L

Explanation:

Given data:

Moles of CO₂ = 5.3 mol

Temperature = 28°C

Pressure = 0.998 atm

Volume occupied = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

28+273 = 301 K

0.998 atm ×V = 5.3 mol × 0.0821 atm.L/ mol.K  × 301 K

V = 130.97 atm.L / 0.998 atm

V  = 131.23 L

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.