How much energy would be required to heat 10.0 g of water at 0 degrees C to 100 degrees C, and change it into steam at 100 degrees C

Q = 4180 J

Explanation:

Given data:

Mass of water = 10.0 g

Initial temperature = 0°C

Final temperature = 100°C

Heat required = ?

Solution:

Specific heat capacity of water is 4.18 j/g.°C.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 100°C - 0°C

ΔT = 100°C

Q = 10.0 g ×4.18 j/g.°C × 100°C

Q = 4180 J

law of conservation of matter

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.