A 50.0 ml sample of 0.200 M HNO2 (weak acid) is titrated with 0.400 M KOH. Calculate the pH after addition of 25 ml KOH (Ky for HNO, is 4.6 x
10-4)
O a 6.67
O b. 7.67
O c.8.23
O d. 9.12

pH = 8.23

Reaction

HNO₂+KOH⇒KNO₂+H₂O

mol HNO₂ = 50 x 0.2 = 10 mlmol

mol KOH = 0.4 x 25 = 10 ml mol

Both of them completely react, resulting in hydrolysis salt which is composed of weak acids and strong bases

Formula :

Kw = water constant = 10⁻¹⁴

Ka = 4.6 x 10⁻⁴

M = anion (salt) concentration =

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

confused

confused             hewdejdnjnjsnd