If the pressure of a gas is quadrupled (4x), how will the volume of the gas change? You answer
must be specific. It must include a number.

Yes. The volume would be 1/4 of the initial volume.

Explanation:

At constant temperature, the pressure of a gas is inversely proportional to the volume of the gas. Hence;

P1V1 = P2V2

where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

If the pressure of a gas is quadrupled;

P2 = 4P1, the equation becomes

P1V1 = 4P1 x V2

Making V2 the subject:

 V2 = P1V1/4P1

        V2 = V1/4

This means that the volume would change by being reduced to 1/4 of the initial volume.

the answer is true.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm