In an aqueous solution, a 0.100 M solution of glucose is prepared with a total volume of 0.150 Liters. If the molar mass of glucose is 180.16 g/mol how many grams must the solution contain?

2.70 g of glucose.

Explanation:

The following data were obtained from the question:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Mole glucose =?

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Cross multiply

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Finally, we shall determine the mass of glucose in the solution as follow:

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Cross multiply

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

Therefore, the solution contains 2.70 g of glucose.

- decrease the number of plants and animals living in the water.

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.