What is the maximum mass, in kilograms, of (NH4)2U2O7 that can be formed from the reaction of 100 kg of water and 100 kg of ammonia with 481 kg of UO2SO4?

Mass of (NH₄)₂U₂O₇ : 410.05 kg

Reaction

2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄

MW UO₂SO₄ :  366.091

MW (NH₄)₂U₂O₇ : 624.131

MW H₂O :  18.0153

MW NH₃ : 17.0306

mol of 100 kg water :

mol of 100 kg ammonia :

mol of UO₂SO₄ :

Limiting reactants : smallest mol ratio(mol : coefficient)

UO₂SO₄ ⇒ Limiting reactants

mol (NH₄)₂U₂O₇ : mol UO₂SO₄

mass (NH₄)₂U₂O₇

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.