HELP ASA Cobalt-60 has a half-life of 5.3 years. A sample measures 0.95g of cobalt-
60. If the sample originally had 5.2g of colbalt-60, determine its age in
years or the time elapsed in years. Round up answer in the nearest whole
number and no additional text or unit. *

13 years

Explanation:

From;

0.693/t1/2 = 2.303/t log (No/N)

Where;

t1/12 = half-life of Cobalt-60 = 5.3 years

t = time taken = the unknown

No = mass of radioactive material originally present = 5.2 g

N = mass of radioactive material at time t = 0.95 g

Substituting values;

0.693/5.3 = 2.303/t log (5.2/0.95)

0.131 = 2.303/t(0.738)

0.131 = 1.6996/t

t =  1.6996/0.131

t = 12.97 years

t = 13 years(to the nearest whole number)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

c

explanation: