Trinitrotoluene (TNT, C7H5N3O6) undergoes complete combustion according to the following balanced chemical equation: C7H5N3O6(s)+214O2(g)→7CO2(g)+32N2(g )+52H2O(l)

If 25.7 g of TNT is combusted in a 0.500 L container filled with O2 at a pressure of 7.02 bar and a temperature of 298 K, calculate the maximum mass of CO2 that could be produced.

Explanation:

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In this case, since the chemical reaction is:

Thus, since we have the initial moles of TNT:

And the initial moles of oxygen given the ideal gas equation:

Given the 1:7 mole ratio between TNT and carbon dioxide and the 21/4:7 mole ratio between oxygen and carbon dioxide, we compute the yielded moles by each reactant:

Thus, since oxygen yields less moles of carbon dioxide than TNT, we infer it is the limiting reactant, therefore, the produced mass of carbon dioxide is:

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