Please help me :) The table below shows data collected in an experiment about gases in inhaled and exhaled air. Percentages of Chemicals in Air O2 CO2 Inhaled 20.94% 0.03% Exhaled 16.37% 4.46% Suppose a similar experiment was set up to measure changes in air composition immediately before and two days after twenty potted plants were placed in a clear, sealed aquarium near a window. Percentages of Chemicals in Air O2 CO2 Before 20.94% 0.03% After ? ? How would the second row of values in the plant experiment most likely compare to the second row of values in the original experiment? Oxygen levels would be higher, but carbon dioxide levels would be lower. Carbon dioxide levels would be higher, but oxygen levels would be lower. Oxygen levels would be higher, but carbon dioxide levels would be the same. Carbon dioxide levels would be higher, but oxygen levels would be the same.

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explanation:

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first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g