Be sure to answer all parts. Show the overall reaction for formation of racemic 3−bromohexane from (E)−3−hexene by entering the structures of the products and reactants in the template provided. Part 1 out of 3 draw structure ... arr draw structure ... + draw structure ... (E)−3−hexene (S)−3−bromohexane (R)−3−bromohexane Racemic product = 50% (S) and 50% (R)

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Explanation:

The mechanism for the formation of bromohexane from hexene has been clearly shown in the image attached to this answer.

Hexene is attacked by HBr and a carbocation is first formed as shown. The carbocation is flat and planar. it can be attacked on either face by the bromide ion.

Attack on either faces yields a racemic mixture of the R and S enantiomer as shown in the image.

You can use the mechanism shown to fill in the structures.