Na2SO3 + 2 AlCl3 --> Al2(SO3)3 + 6 NaCl Using the above reaction, suppose (1.760x10^2) grams of Na2SO3 were added to (6.5x10^1) grams of AlCl3, how much (in g) of NaCl was produced once the reaction was run to completion?

Mass NaCl produced : 171.81 g

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Na₂SO₃ : 176 g

MW : 126,043 g/mol

mol :

AlCl₃ : 65 g

MW : 133,34 g/mol

mol :

Reaction

Na₂SO₃ + 2 AlCl₃ ⇒ Al₂(SO₃)₃ + 6NaCl

limiting reactants:

mol ratio(mol/coefficient) Na₂SO₃ : 2 AlCl₃ =

AlCl₃ ⇒ limiting reactants(smaller ratio)

mol NaCl from limiting reactants :

mass NaCl

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles