If 5.90 kJ of heat evolved from a neutralization of 156 mmols of a monoprotic acid, what is the molar heat of neutralization (in kJ/mol) of that acid

37.82kJ/mol is the molar heat of neutralization

Explanation:

The neutralization of a monoprotic acid, HX, with NaOH as example is:

HX + NaOH → H₂O + NaX + ΔH

Where ΔH is molar heat of neutralization (The heat that is released when 1 mole of HX is neutralized).

As neutralization of 156mmol = 0.156mol HX release 5.90kJ. When 1 mole is neutralized the released heat is:

ΔH = 5.90kJ / 0.156moles

ΔH = 37.82kJ/mol is the molar heat of neutralization

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell

gas and precipitate r the correct answers