How much water is produced when 89m of H2 is reacted with 64gm of O2?

Mass of water produced = 801 g

Explanation:

Given data:

Mass of water produced = ?

Mass of H₂ = 89 g

Mass of oxygen = 64 g

Solution:

Chemical equation:

2H₂ + O₂      →      2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar moles

Number of moles = 89 g/ 2 g/mol

Number of moles = 44.5 mol

Number of moles of oxygen:

Number of moles = mass/molar moles

Number of moles = 64 g/ 2 g/mol

Number of moles = 32 mol

Now we will compare the moles of water with oxygen and hydrogen.

                 H₂             :            H₂O

                  2              :              2

                  44.5         :            44.5

                 O₂             :             H₂O

                  1               :               2

               32               :              2/1×32 =64 mol

Number of moles of water produced by hydrogen are less thus it yield is limit by hydrogen.

Mass of water:

Mass = number of moles × molar mass

Mass = 44.5 mol ×  18 g/mol

Mass = 801 g

the millers tale is the answer.

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.