How many so32- ions are contained in 99.6 mg of na2so3? the molar mass of na2so3 is 126.05 g/mol.

Answer : The number of ions are,

Explanation : Given,

Mass of = 99.6 mg = 0.0996 g

Conversion used : (1 mg = 0.001 g)

Molar mass of = 126.05 g/mole

First we have to calculate the moles of .

Now we have to calculate the number of .

As we know that, dissociate to give 2 moles of and 1 mole of .

From this we conclude that,

As, 1 mole contains number of ions

So,  mole contains number of ions

Therefore, the number of ions are,

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

the atomic mass is the bottom number on the element.

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