How many grams of carbon dioxide are produced when 16.0 g of methane and 48.0 g of oxygen gas combust?
Molar mass of CH4 = 16.0 g/mol
Molar mass of O2 = 32.0 g/mol
Molar mass of CO2 = 44.0 g/mol

Mass of CO₂ = 33 g

Further explanation  

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.  

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O  

Reaction

CH₄ + 2O₂⇒CO₂ + 2H₂O

mol CH₄ :

mol O₂ :

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients

Because O₂ ratio smaller then O₂ becomes the limiting  reactants

So mol CO₂ from limiting reactants

mol CO₂ :

mass CO₂ :

Ithink the answer is a or d.

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.