The initial pressure is 4.0 atm and the initial volume is 30.0 mL. If the pressure is increased to 8.0 atm, what will be the new volume?

New volume, V2 = 15mL

Explanation:

Given the following data;

Initial volume, V1 = 30mL

Initial pressure, P1 = 4atm

New pressure, P2 = 8atm

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

Substituting into the equation, we have;

V2 = 15mL

Therefore, the new volume is 15 mL.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%