DQ 2. Identify the anode and cathode in the Cu-Pb voltaic cell. Provide the balanced half-reactions that describe the reaction taking place at each electrode. Combine the two half-reactions to provide the net ionic equation that represents the overall reaction within the Cu-Pb voltaic cell.

Identify the anode and cathode in the Cu-Pb voltaic cell -

                                       Cu (s) ---> Cu 2+ (aq) + 2 e-

                          Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

A galvanic cell or voltaic cell reaction is a redox reaction that takes place in two half-reactions oxidation and reduction. At anode oxidation reaction and at cathode reduction reaction takes place.  

anode:

                              Cu (s) ---> Cu 2+ (aq) + 2 e-

cathode:                

                                Pb 2+ (aq) + 2 e- ---> Pb (s)

combined:

                          Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

Thus, Identify the anode and cathode in the Cu-Pb voltaic cell -

                                       Cu (s) ---> Cu 2+ (aq) + 2 e-

                          Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

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Anode: Pb

Cathode: Cu

Overall cell reaction:

Pb(s) + Cu^2+(aq) > Pb^2+(aq) + Cu(s)  

Explanation:

Anode half reaction;

Pb(s) > Pb^2+(aq) + 2e                -0.13 V

Cathode half reaction;

Cu^2+(aq) + 2e > Cu(s)             +0.34 V

Overall cell reaction;

Pb(s) + Cu^2+(aq) > Pb^2+(aq) + Cu(s)    

Pb is the anode because it has a more negative reduction potential. This implies that it is above copper in the electrochemical series. In any voltaic cell comprising of a metal cathode and anode; the metal that is higher in the electrochemical series serves as the anode while the other metal serves as the cathode.

answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

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