gBe sure to answer all parts. Nicotine can be made when the following ammonium salt is treated with Na2CO3. Determine a stepwise mechanism for this reaction. h5sm775 nicotine Part 1 out of 3 Choose the first step of the mechanism: h5sm775003 h5sm775002

Kindly check the attached pictures.

Explanation:

For the reaction between ammonium salt and Na2CO3, in the reaction mechanism, there are going to be four steps for the production of nicotine. The chemical species to monitor here are the Na2CO3 and the starting material which has the amine group attached to it.

STEP ONE: Dissociation of the Na2CO3.

Na2CO3 <=========> 2Na^+ + CO3^2-

STEP TWO: (will be shown in the attached picture). It is the abstraction of H^+ from the amine in the starting material.

STEP THREE: (will be shown in the attached picture). It is the formation of a cyclic compound due to nucleophilic reaction.

STEP FOUR: (will be shown in the attached picture). It involve the the deprotonation and this is the final phase.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

i think   the answer is c hope i'm right