use the gizmos to mix 200 G of copper at 100 C with 1000 g of water at 20 C whatis the final temperature

Explanation:

mass of copper = 200 g at temperature 100°C

mass of water = 1000 g at 20⁰C

Let the final temperature be T .

specific heat of copper = .385 J per gram

specific heat of water = 4.182 J per gram

heat lost = mass x specific heat x fall of temperature

heat lost by copper

= 200 x .385 x ( 100 - T )

heat gained by water

= 1000 x 4.182 x ( T - 20 )

heat lost by copper = heat gained by water

200 x .385 x ( 100 - T )  = 1000 x 4.182 x ( T - 20 )

7700 - 77 T = 4182 T - 83640

4259 T  = 91340

T = 21.44⁰C .

the answer to your question is c