I have a few question please help its due in a few hours 1. Determine the specific heat of a certain metal if a 450 gram sample of it loses 34,500J of heat as its temperature drops by 97K 2. The temperature of a 25 gram sample of a certain metal drops by 103 K as it loses 2600 joules of heat. What is the specific heat of the metal?

3.What is the final temperature after 840 Joules is absorbed by 10.0g of water at 298K?
(please show steps)

c = 0.79 j/g.K

c = 1 j/g.K

T2 = 123.1 K

Explanation:

1)

Given data:

Mass of metal = 450 g

Heat loses = 34,500 j

Temperature drop = ΔT  = 97 K

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

34500 j = 450 g ×c × 97 K

34500 j = 43650 g.K ×c

c = 34500 j/43650 g.K

c = 0.79 j/g.K

2)

Given data:

Mass of metal = 25 g

Heat loses = 2600 j

Temperature drop = ΔT  = 103 K

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

2600 j = 25 g ×c × 103 K

2600  j = 2575 g.K ×c

c = 2600 j/2575 g.K

c = 1 j/g.K

3)

Given data:

Mass of water = 10 g

Heat absorbed  = 840 j

Initial temperature drop = 298 K

Final temperature = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

840 j = 10 g ×4.18 j/g.K × [T2 - 103 K]

840 j = 41.8 J/K ×  [T2 - 103 K]

840 J/41.8 J/ K = T2 - 103 K

20.1 k = T2 - 103 K

T2 = 20.1 K + 103 K

T2 = 123.1 K

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )