In an experiment, two unknown compounds (one an alcohol and the other an amine) of equal molecular mass were heated. The result of the experiment shows that Compound A boiled at a lower temperature than Compound B. Which of the following correctly explains the identity of Compound A and why this was the result? (4 points)

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.
It is an amine; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.

Explanation:

The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.

Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.

A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

 Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.

  The order of strength of the bond is;

             HF  > HO > HN

In amines we have the HN hydrogen bonds, for alcohol, it is the HO hydrogen bonds.

So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.