The orbital diagram shows the valence electrons of sulfur, which has 16 electrons. If the electrons were added to the atom one at a time, which would be the last electron to occupy an orbital?

3px

Explanation:

The electronic configuration of sulphur is given as;

1s2 2s2 2p6 3s2 3px2 3py1 3pz1.

Recall that in accordance with Hund's rule, electrons occur singly first before pairing takes place during the filling of degenerate orbitals.

The last sub-level into which electrons are filled in sulphur is the 3p sub-level having three degenerate orbitals, 3px, 3py and 3pz.

According to Hund's rule, these levels are first singly filled before pairing begins. Hence the last electron in sulphur goes into the 3px orbital.

answer; protein;

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: