A student measures the average atomic mass of an element to be 78.93 amu The actual atomic mass is 80.29 amu Calculate the students percent error round your answer to two decimal place

Percent error = -1.69%

Explanation:

Given data:

Measured value of average atomic mass = 78.93 amu

Actual  value of average atomic mass = 80.29 amu

Percent error = ?

Solution:

Formula:

Percent error = [measured value - actual value /actual value] × 100

Percent error = [ 78.93 amu - 80.29 amu/80.29 amu ] × 100

Percent error = [-1.36 /80.29 amu ] × 100

Percent error = -1.69%

Negative sign shows that measured value is less than actual value.

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