Calculate the energy of a photon of infrared light that has a frequency of 2.40 x 10^12 Hz
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According to the law of energy, it states that energy can never be created nor be destroyed. It can only transfer from one thing to another.

These are the various type of energy:-

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)  

After putting the value:-

After solving the equation, the energy is:-

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹J

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Option C. 1.60×10¯²¹ J

Explanation:

The following data were obtained from the question:

Frequency (f) = 2.40×10¹² Hz

Energy (E) =..?

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

Frequency (f) = 2.40×10¹² Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =..?

E = 6.63×10¯³⁴ × 2.40×10¹²

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹ J

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

is there any options? maybe im just not seeing them but i need the options to

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