What is the mass of 0.250 mol of chlorotrifluoromethane, CCIF3? A. 26.1 g
B. 104 g
C. 4.78 x 10-3 g
D. 52.2g

26.1g

Explanation:

Cclf3

=35.5

F=54/101.5

Mass=mol*mm

=0.25*1015

=26.1g

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole