A 293.9 mL sample of a 0.275 M solution is left on a hot plate overnight; the following morning the solution is 1.10 M. What volume of solvent in mL has evaporated from the 0.275 M solution

220.4mL were evaporated

Explanation:

First, we are going to calculate the moles of the solution. Then, with the new concentration we can solve the volume of the solution and the evaporated volume:

Moles initial solution:

293.9mL = 0.2939L * (0.275mol / L) = 0.08082 moles of solution.

As the new concentration is 1.10M, the new volume must be:

0.08082 moles of solution * (1L / 1.10mol) = 0.07348L =

73.5mL you have still present in you solution

And evaporated volume is:

293.9mL - 73.5mL =

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i