What is the minimum amount of water is needed to dissolve 3.0 mol potassium dichromate (k2cr2o7)

6.79 litres

Explanation:

Potassium dichromate is K2Cr2O7

Its molar mass = 294.18 g/mol

If,

1 mole = 294.18 g

3 mole = 3 x 294.18 g

= 882.54 g

Solubility of K2Cr2O7 is

4.9 g/100 mL at 0⁰c

13 g/100 mL at 20⁰c

102 g/100 mL at 100⁰c

No specific temperature is given so I have used 20⁰C since it is close to room temperature.

at 20⁰C:

13 g of K2Cr2O7 would dissolve in = 100 mL

So 1 g of K2Cr2O7 dissolves in = (100/13)

= 7.692

882.54 g of K2Cr2O7 dissolves in = 882.54 x 7.692

= 6788.59mL

We convert to litres

= 6.79 L

the answer is a and have a great day

the answer is 303.15 or 303