What is the longest wavelength of electromagnetic radiation capable of ionizing this hydrogen atom in an excited state

Hello. This question is incomplete. The full question is:

Calculate the energy required to ionize a hydrogen atom to an excited state where the electron is initially in the n = 5 energy level. Report your answer in kilojoules.

What is the longest wavelength of electromagnetic radiation capable of ionizing this hydrogen atom in an excited state? Report your answer in nanometers.

2282 nm

Explanation:

You should start this calculation using the formula: E = (-13.6 / n ^ 2) * eV. This formula refers to the amount of energy required in this system, mentioned in the question above.

Replacing the formula with the values presented in the question we have:

E = (13.6 / 25) * 0.544V = (1,602 × 10 ^ -19) * (0.544 × 10 ^ −3) = 8.71 × 10 ^ −23 kJ

Found that result. We must use the formula:

E = hc / λ

λ = hc / E > [(6,626 × 10 ^ −34) * (3 × 10 ^ 8)] /(8.71×10^−23) * 10 ^ 3 =

2282 nm

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.