At what temperature would a 1.65 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86 ∘C/m .

-5.83 °C

Explanation:

Step 1: Given data

Step 2: Calculate the freezing point depression

The freezing point depression is a colligative property that can be calculated using the following expression.

ΔTf = i × m × Kf

ΔTf = 1.9 × 1.65 m × 1.86 °C/m

ΔTf = 5.83 °C

Step 3: Calculate the freezing point of the solution

The freezing point of pure water is 0°C. The freezing point of the solution is:

0 °C - 5.83°C = -5.83 °C

what are the choices?

answer: h+ its less than oh

explanation: