Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17. g of hexane is mixed with 101. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

52g of carbon dioxide

Explanation:

Liquid hexane + gaseous oxygen --> Carbon dioxide + gaseous water

The balance chemical equation is given as;

C6H12 + 9O2 --> 6CO2 + 6H2O

From the stochiometry of the reaction;

1 mol of hexane (86g) would consume 9 mol of oxygen (144g) to form 4 mol of carbon dioxide (264g)

The limiting reactant in this equation is hexane as it would run out before oxygen. This means hexane determines how much of the carbon dioxide is formed.

86g of hexane = 264g of crbon dioxide

17g of hexane = xg of carbon dioxide

x = 17 * 264 / 86 =  52g of carbon dioxide

the answer for sodium is 0.186

the answer for rubidium is 0.251