How many grams of glycine amide should be added to 1.00 g of glycine amide hydrochloride to give 100 mL of solution with pH 8.00

0.4235 g of glycine amide should be added

Explanation:

From the given information:

The equation of the reaction can be illustrated as:

where:

mass of glycine amide hydrochloride = 1.00 g

Suppose x be the amount of (in grams) of glycine amide that is required to be added; Then:

0.0905 M

So, For [B} i.e, for glycine amide

[B] = 0.135x  M

∴

The log of the above question can be computed as:

8.00 = 8.20 +

8.00 - 8.20 =

-0.20 =

1.49 x =

1.49 x = 0.631

x = 0.631/1.49

x =  0.4235 g

b i think it’s a water wheel turning in a stream

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.