Ignoring the CuSO4, and based solely on the volume and molarity of the Na2S(aq), how many grams of CuS(s) would be produced by this

 0.019122 grams of CuS(s) would be produced .

Explanation:

Given , volume of is 4ml = 0.004 L

            volume of is 2ml = 0.002 L

Moles of = Molarity x volume (L)

                          = 0.1M x 0.004 L

                              = 0.0004 moles

Moles of = 0.1M  x 0.002 L

                            = 0.0002 moles

1 mole of 1 mole of

Therefore , 0.0002 moles 1mole of

Mass of =  Moles x molar mass

                     = 0.0002 x  95.611

                  = 0.019122 grams .

Hence the answer is 0.019122 grams.