Net ionic equation for Sb(OH)3 + Na2S?

The net ionic equation is a chemical equation that shows only those ions that are involved directly in the formation of the final product. The net ionic equation for the given reaction is .

It is a chemical equation that shows only those ions that are involved directly in the formation of the final product.

So, molecular equation,

Now, write the ionic equation,

To make a Net ionic equation cancel all the duplicate ions present on both sides of the equation.

Therefore, the net ionic equation for the given reaction is .

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2 Sb3+ (aq) + 3 S2- (aq) ⇒ Sb2S3 (s)

 Explanation:

Molecular equation for Sb(OH)3 + Na2S

2 Sb(OH)3 (aq) + 3 Na2S (aq) ⇒ Sb2S3 (s) + 6 NaOH (aq)

Ionic equation for Sb(OH)3 + Na2S

2 Sb3+ + 6 OH-  + 6 Na+ + 3 S2- ⇒ Sb2S3 + 6 Na+ + 6 OH-

To get the net ionic, any duplications on the left or right side would be canceled.

∴ Thus, the net ionic equation for Sb(OH)3 + Na2S is 2 Sb3+ (aq) + 3 S2- (aq) ⇒ Sb2S3 (s)

it would be a gas formation