Chegg Write the reduction half-reaction occurring at the C(s) electrode. Include physical states. ( Note the C(s) serves as a conductor). (2) Write the oxidation half reaction. (3) Write the net cell reaction.

(1). 1/2 Cl2 + e^- ++> Cl^-.

(2). Cd(s) > Cd^2+(aq) + 2e^-.

(3). Cl2(g) + Cd(s) > Cd^2+(aq) + 2Cl^-(aq).

Explanation:

There are different kinds or types of chemical reactions some of them are combination reaction, decomposition reaction, double decomposition reaction, elimination reaction, reduction- oxidation reaction (REDOX) and many more.

So, this question asked us about the reduction- oxidation(REDOX) reaction. This kind of reaction deals with changes in electron or oxidation rates.

For the reduction part, we have;

1/2 Cl2(g) + e^- ++> Cl^-(aq).

For the oxidation part, we have;

Cd(s) > Cd^2+(aq) + 2e^-.

This, the overall reaction gives:

Cl2(g) + Cd(s) > Cd^2+(aq) + 2Cl^-(aq).

the millers tale is the answer.