An experiment was carried out to observe whether temperature affects rate of diffusion. Beaker A had ice water and beaker B had hot water. Into each beaker 2 drops of food colouring was added and time was started simultaneously. In which beaker will the rate be fasted

Explanation:

The temperature increases the rate of diffusion process . Due to increase in temperature , molecules start moving fast . Hence their  ability to diffuse is also increased .

Hence in hot water , the colouring compound will diffuse fast and  therefore , rate of colouration will be fast in hot water . In cold water , it will be slow . In ice chilled water . It will be further slowed down .

it should be p1 v1 = p2 v2

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.