A gas occupies a volume of 500 milliliter sat pressure of 38.0 kPa and a temperature of 298K. At what temperature will the gas occupy a volume of 250 milliners and have a pressure of 76.0 kPa

T₂ = 298 K

Explanation:

Given data:

Initial volume = 500 mL

Initial pressure = 38.0 KPa

Initial temperature = 298 K

Final temperature= ?

Final pressure = 76.0 KPa

Final volume = 250 mL

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = = P₂V₂T₁ / P₁V₁

T₂ = 76.0 KPa × 250mL × 298 K / 38.0 KPa × 500 mL  

T₂ = 5662000 KPa.mL. K /19000 KPa. mL

T₂ = 298 K

the awnser is group 12