A lead fishing weight of 39.7g is submerged in a graduated cylinder of water containing 75.0mL of water. The water level will increase to what volume in the cylinder?

78.5 mL

Explanation:

Step 1: Given data

Mass of the lead fishing weight: 39.7 g

Volume of water in the graduated cylinder: 75.0 mL

Step 2: Calculate the volume of the lead fishing weight

The density of lead is 11.34 g/mL.

39.7 g × (1 mL/11.34 g) = 3.50 mL

Step 3: Calculate to what volume will increase the water level

The final volume of water will be equal to its initial value plus the volume displaced by the lead fishing weight.

V = 75.0 mL + 3.50 mL = 78.5 mL

the answer is   c.) 1575 j.

explanation:

level 4 to level 2 : ))