How much heat is required to melt 42.0 grams of water at 0*C?
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Heat required to melt 42 g if ice is 13,860 J

Explanation:

The amount of heat required to melt  grams of water at 0°C is given as follows;

The mass of the ice (water), m = 42 g

The latent heat of fusion of ice Δ= 330 J/g

Therefore, heat required to melt 42 grams is given as follows;

Heat required to melt ice = Mass of the ice, m × The specific latent heat of fusion of the ice, Δ

Heat required to melt 42 g if ice = m × Δ = 42 g × 330 J/g = 13,860 J

Heat required to melt 42 g if ice = 13,860 J.

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