What is the specific heat of a metal if the temperature of a 12.5 g sample increases from 19.5 C to 33.6 C when it absorbs 37.7 J of heat.

0.213 J/g°C

Explanation:

To calculate specific heat of the metal, the formula is used:

Q = m × c × ∆T

Where Q = amount of heat

m = mass

c = specific heat

∆T = change in temperature

According to this question, Q = 37.7 J, m= 12.5 g, initial temperature= 19.5 °C, final temperature = 33.6°C, c=?

Q = m × c × ∆T

37.7 = 12.5 × c × (33.6-19.5)

37.7 = 12.5c × 14.1

37.7 = 176.25c

c = 37.7/176.25

c = 0.2139

Hence, the specific heat of the metal is 0.213 J/g°C

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

what is the average time it took the car to travel 0.25 meters?

⇒ 2.23 seconds

what is the average time it took the car to travel 0.50 meters?

⇒ 3.13 seconds