How many milliliters of 10.7 M perchloric acid solution should be used to prepare 5.50 L of 0.200 M

102.8 mL.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M1) = 10.7 M

Molarity of diluted solution (M2) = 0.2 M

Volume of diluted solution (V2) = 5.5 L

Volume of stock solution needed (V1) =.?

The volume of the stock solution needed can be obtained by using the following formula:

M1V1 = M2V2

10.7 × V2 = 0.2 × 5.5

10.7 × V2 = 1.1

Divide both side by 10.7

V2 = 1.1 / 10.7

V2 = 0.1028 L

Finally, we shall convert 0.1028 L to millilitres (mL) in order to obtain the desired result. This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.1028 L = 0.1028 L × 1000 mL / 1 L

0.1028 L = 102.8 mL

Therefore, 0.1028 L is equivalent to 102.8 mL.

Thus, 102.8 mL of the stock solution (i.e perchloric acid) is needed.

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell