How many joules of thermal energy are required to boil away the 100 g of ethanol? The latent heat of vaporization for ethanol is 846 J/g. *

Q = 84.6 kJ

Explanation:

Given that,

The latent heat of vaporization for ethanol, L = 846 J/g

Mass, m = 100 g

We need to find the thermal energy required to boil away the ethanol. It can be given by the formula as follows :

Q=mL

Q = 100 g × 846 J/g

Q = 84600 J

or

Q = 84.6 kJ

Hence, thermal energy is 84.6 kJ.