We consider the following chemical equation: 6 HCl + Fe2(CO3)3 +3 Ca(OH)2
- 2 FeCl3 + 3 CaCO3 + 6 H2O
How many moles of CaCO3 would be obtained from 0.7 moles of Fe2(CO3)3, 2.2 moles of Ca(OH)2 and
2.75 moles of HCI? How many grams of FeCl3 would be produced?
sosss :(

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answer is 75.0%.

explanation: