A fault cuts across several layers of rock. Which conclusion can be made?(1 point) The fault is younger than the layers of rock, according to the law of inclusion.

The fault is older than the layers of rock, according to the law of inclusion.

The fault is younger than the layers of rock, according to the law of crosscutting.

The fault is older than the layers of rock, according to the law of crosscutting.

The fault is younger than the layers of rock, according to the law of crosscutting.

Explanation:

Then Law of Crosscutting which was described by James Hutton explains that whenever a fault is seen on a rock, the fault will always be younger than the rock it is one.

This makes sense because if there was no rock in the first place, the fault would not have cut through it. But because there was a rock and an object exacted a force in order to move through the rock, the fault appeared showing that the rock came first, then came the fault.

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation:

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol