A 7.212 g sample of hydrated salt is heated until a constant mass is obtained. The mass of the anhydrous salt is 3.524. What is the percent by mass of water in the original hydrated salt sample in % H20?

51.14%

Explanation:

The following data were obtained from the question:

Mass of hydrated salt = 7.212 g

Mass of anhydrous salt = 3.524 g

Percentage mass of water =..?

Next, we shall determine the mass of the water in the hydrated salt. This can be obtained as follow:

Mass of hydrated salt = 7.212 g

Mass of anhydrous salt = 3.524 g

Mass of water =.?

Mass of water = (Mass of hydrated salt) – (Mass of anhydrous salt)

Mass of water = 7.212 – 3.524

Mass of water = 3.688 g

Finally, we shall determine the percentage mass of water in the hydrated salt as follow:

Percentage of water

= mass of water /mass of hydrated salt × 100

Percentage of water = 3.688/7.212 × 100

Percentage of water = 368.8/7.212

Percentage of water = 51.14%

Therefore, the percentage of water in the hydrated salt is 51.14%

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)