Chemistry, 07.10.2020 14:01 tusharchandler124

Show work 7. How many mm are there in 2.3Mm?
8. Copper has a density of 6.55g/cmº. A. piece of metal has a mass of 48.3g and a volume of 7.2cm.
Is this metal copper?
9. What is the mass of a liquid whose volume is 6.0 mL and a density of 1.3 g/cm??
10. You have 3.50 L of a liquid, whose density is 2.3g/cm3. What is it's Mass?

Answers: 2

Show answers

Answers

Answer from: mahmudabiazp3ekot

7 = 2.3× 10⁺⁹ mm

8 = The density of copper is 6.55g/cm³ so the given metal is not copper.

9 = mass of liquid is 7.8 g

10 = mass of liquid is 8050 g.

Explanation:

7. How many mm are there in 2.3Mm?

mm is the symbol of millimeter.

Mm is the symbol of megameter.

1 mm = 10⁻⁹Mm

so in order to convert 2.3Mm into mm we will multiply the given value with 10⁺⁹

2.3 mm × 10⁺⁹ = 2.3× 10⁺⁹ mm

8. Copper has a density of 6.55g/cmº. A. piece of metal has a mass of 48.3g and a volume of 7.2cm.

Is this metal copper?

Given data:

Density of copper = 6.55 g/cm³

Mass of metal = 48.3 g

Volume of metal = 7.2 cm³

Is the metal is copper = ?

Solution:

The given problem will be solved through the density formula.

D = m/v

We will put the values in formula to calculate the density.

d = 48.3 g/ 7.2 cm³

d = 6.71 g/cm³

The density of copper is 6.55g/cm³ so the given metal is not copper.

9. What is the mass of a liquid whose volume is 6.0 mL and a density of 1.3 g/cm??

Given data:

Volume of liquid = 6.0 mL (1 mL = 1cm³)

Density of liquid = 1.3 g/cm³

Mass of liquid = ?

Solution:

Formula:

D = m/v

By putting the values in formula.

1.3 g/cm³ = m / 6 cm³

m = 1.3 g/cm³ × 6 cm³

m = 7.8 g

mass of liquid is 7.8 g.

10. You have 3.50 L of a liquid, whose density is 2.3g/cm3. What is it's Mass?

Given data:

Volume of liquid = 3.50L (3.50 ×1000 = 3500 cm³)

Density of liquid = 2.3g/cm³

Mass of liquid = ?

Solution:

Formula:

D = m/v

By putting the values in formula.

2.3g/cm³ = m /3500cm³

m = 2.3 g/cm³ × 3500 cm³

m = 8050 g

mass of liquid is 8050g.

Answer from: Quest

Perimeter? wheres the answers

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

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Show work 7. How many mm are there in 2.3Mm?
8. Copper has a density of 6.55g/cmº. A. piece o...

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