A marble has a density of 11 g/cm3 and when dropped in a graduated cylinder increases the water level from 2 mL to 4 mL of volume. What is the mass of the marble in grams?

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

density = 11 g/cm³

volume = final volume of water - initial volume of water

volume = 4 - 2 = 2 mL

But 1 mL = 1 cm³

2 mL = 2 cm³

volume = 2 cm³

The mass of the marble is

mass = 11 × 2

We have the final answer as

Hope this helps you

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

level 4 to level 2 : ))