1. How much heat, in calories, is needed to raise the temperature of 415 grams of water from 25.5°C to 65.2°C? (3 points for set-up: 1 for the answer)

16475.5 calories.

Explanation:

The following data were obtained from the question:

Mass (M) = 415 g

Initial temperature (T1) = 25.5 °C

Final temperature (T2) = 65.2 °C

Specific heat capacity (C) = 1 cal/g°C

Heat (Q) required =?

Next, we shall determine the change in temperature of the water. This can be obtained as follow:

Initial temperature (T1) = 25.5 °C

Final temperature (T2) = 65.2 °C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 65.2 – 25.5

Change in temperature (ΔT) = 39.7 °C

Finally, we shall determine the heat required to raise the temperature of the water as follow:

Mass (M) = 415 g

Specific heat capacity (C) = 1 cal/g°C

Change in temperature (ΔT) = 39.7 °C

Heat (Q) required =?

Q = MCΔT

Q = 415 × 1 × 39.7

Q = 16475.5 calories.

Therefore, the heat required to raise the temperature of the water is 16475.5 calories.

why is arctic sea ice important? arctic sea ice keeps the polar regions cool and moderate global climate. sea ice has a bright surface; 80 percent of the sunlight that strikes it is reflected back into space. as sea ice melts in the summer, it exposes the dark ocean surface.